3b^2-441=0

Solution for 3b^2-441=0 equation:

3b^2-441=0

a = 3; b = 0; c = -441;
Δ = b2-4ac
Δ = 02-4·3·(-441)
Δ = 5292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5292}=\sqrt{1764*3}=\sqrt{1764}*\sqrt{3}=42\sqrt{3}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42\sqrt{3}}{2*3}=\frac{0-42\sqrt{3}}{6}
=-\frac{42\sqrt{3}}{6}
=-7\sqrt{3}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42\sqrt{3}}{2*3}=\frac{0+42\sqrt{3}}{6}
=\frac{42\sqrt{3}}{6}
=7\sqrt{3}
$